.03x^2-8x+700=624

Solution for .03x^2-8x+700=624 equation:

.03x^2-8x+700=624

We move all terms to the left:

.03x^2-8x+700-(624)=0

We add all the numbers together, and all the variables

.03x^2-8x+76=0

a = .03; b = -8; c = +76;
Δ = b2-4ac
Δ = -82-4·.03·76
Δ = 54.88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-\sqrt{54.88}}{2*.03}=\frac{8-\sqrt{54.88}}{0.06}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+\sqrt{54.88}}{2*.03}=\frac{8+\sqrt{54.88}}{0.06}
$